西普学院CTF编程题之考考你的程序功底

site:http://www.simplexue.com/ctf/examctfdetail/4  考考你的程序功底

题目要求:

给定一个20行20列的数表,求其中在一条线上(行、列、两个对角线)连续4个数的乘积的最大值。
输入最大的值然后就可以点击获取key值

图片如下:(居然给图片,要知道输入这20*20的数组多累人,还怕出错)
sx1
程序如下,注意缩进,亲测有效:) have fun!
# -*- coding: cp936 -*-

#初始化二维数组,:(
a = [[8, 2, 22, 97, 38, 15, 0, 40, 0, 75, 4, 5, 7, 78, 52, 12, 50, 77, 91, 8],
    [49, 49, 99, 40, 17, 81, 18, 57, 60, 87, 17, 40, 98, 43, 69, 48, 4, 56, 62, 0],
    [81, 49, 31, 73, 55, 79, 14, 29, 93, 71, 40, 67, 53, 88, 30, 3, 49, 13, 36, 65],
    [52, 70, 95, 23, 4, 60, 11, 42, 69, 24, 68, 56, 1, 32, 56, 71, 37, 2, 36, 91],
    [22, 31, 16, 71, 51, 67, 63, 89, 41, 92, 36, 54, 22, 40, 40, 28, 66, 33, 13, 80],
    [24, 47, 32, 60, 99, 3, 45, 2, 44, 75, 33, 53, 78, 36, 84, 20, 35, 17, 12, 50],
    [32, 98, 81, 28, 64, 23, 67, 10, 26, 38, 40, 67, 59, 54, 70, 66, 18, 38, 64, 70],
    [67, 26, 20, 68, 2, 62, 12, 20, 95, 63, 94, 39, 63, 8, 40, 91, 66, 49, 94, 21],
    [24, 55, 58, 5, 66, 73, 99, 26, 97, 17, 78, 78, 96, 83, 14, 88, 34, 89, 63, 72],
    [21, 36, 23, 9, 75, 0, 76, 44, 20, 45, 35, 14, 0, 61, 33, 97, 34, 31, 33, 95],
    [78, 17, 53, 28, 22, 75, 31, 67, 15, 94, 3, 80, 4, 62, 16, 14, 9, 53, 56, 92],
    [16, 39, 5, 42, 96, 35, 31, 47, 55, 58, 88, 24, 0, 17, 54, 24, 36, 29, 85, 57],
    [86, 56, 0, 48, 35, 71, 89, 7, 5, 44, 44, 37, 44, 60, 21, 58, 51, 54, 17, 58],
    [19, 8, 81, 68, 5, 94, 47, 69, 28, 73, 92, 13, 86, 52, 17, 77, 4, 89, 55, 40],
    [4, 52, 8, 83, 97, 35, 99, 16, 7, 97, 57, 32, 16, 26, 26, 79, 33, 27, 98, 66],
    [88, 36, 68, 87, 57, 62, 20, 72, 3, 46, 33, 67, 46, 55, 12, 32, 63, 93, 53, 69],
    [4, 42, 16, 73, 38, 25, 39, 11, 24, 94, 72, 18, 8, 46, 29, 32, 40, 62, 76, 36],
    [20, 69, 36, 41, 72, 30, 23, 88, 34, 62, 99, 69, 82, 67, 59, 85, 74, 4, 36, 16],
    [20, 73, 35, 29, 78, 31, 90, 1, 74, 31, 49, 71, 48, 86, 81, 16, 23, 57, 5, 54],
    [1, 70, 54, 71, 83, 51, 54, 69, 16, 92, 33, 48, 61, 43, 52, 1, 89, 19, 67, 48]]

#存放四种不同计算结果的数组
aa = [[]for i in range(4)]

#计算同行、同列
for j in range(20):
    for i in range(17):
        aa[0].append(a[j][i]*a[j][i+1]*a[j][i+2]*a[j][i+3])
        aa[1].append(a[i][j]*a[i+1][j]*a[i+2][j]*a[i+3][j])

#计算对角线和反对角线
for i in range(17):
    for j in range(17):
        aa[2].append(a[i][j]*a[i+1][j+1]*a[i+2][j+2]*a[i+3][j+3])
        aa[3].append(a[i+3][j]*a[i+2][j+1]*a[i+1][j+2]*a[i][j+3])

#输出每个值中的最大值
for i in range(len(aa)):
    print max(aa[i])

 

输出的是四个不同方向的最大值,就四个值

48477312
51267216
40304286
70600674

输入最大值,拿到Key

KEY:IL0V3Pr0Gr4m@#!!

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